-4-6a^2=-64

Solution for -4-6a^2=-64 equation:

-4-6a^2=-64

We move all terms to the left:

-4-6a^2-(-64)=0

We add all the numbers together, and all the variables

-6a^2+60=0

a = -6; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-6)·60
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*-6}=\frac{0-12\sqrt{10}}{-12}
=-\frac{12\sqrt{10}}{-12}
=-\frac{\sqrt{10}}{-1}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*-6}=\frac{0+12\sqrt{10}}{-12}
=\frac{12\sqrt{10}}{-12}
=\frac{\sqrt{10}}{-1}
$